sodium,2,3-dihydroxypropyl [(2R)-3-hexadecanoyloxy-2-[(Z)-octadec-9-enoyl]oxypropyl] phosphate(268550-95-4)名称与标识符
名称
中文别名:
POPG钠盐;2,3-二羟丙基[2-(油酰氧基)-3-(棕榈酰氧基)丙基]丙基磷酸钠;1-棕榈酰基-2-油酰基磷脂酰甘油钠盐;1-棕榈酰-2-油酰基-sn-甘油-3-磷酰-(1'-外消旋-甘油)钠盐;1-棕榈酰-2-油烯基-sn-甘油-3-磷酰-rac-(1-甘油)钠盐;
英文别名:
sodium,2,3-dihydroxypropyl [(2R)-3-hexadecanoyloxy-2-[(Z)-octadec-9-enoyl]oxypropyl] phosphate;1-palmitoyl-2-oleoyl-sn-glycero-3-phospho-(1''-rac-glycerol) (sodium salt);1-palmitoyl-2-oleoyl-sn-glycero-3-phospho-(1'-rac-glycerol) (sodium salt);(9Z)-9-Octadecenoic acid (1R)-1-[[[(2,3-dihydroxypropoxy)hydroxyphosphinyl]oxy]methyl]-2-[(1-oxohexadecyl)oxy]ethyl ester monosodium salt;1-Palmitoyl-2-oleoyl-sn-glycero-3-phospho-(1′-rac-glycerol) sodium salt;1-Palmitoyl-2-oleoyl-sn-glycero-3-phosphoglycerol sodium salt;1-hexadecanoyl-2-(9Z-octadecenoyl)-sn-glycero-3-phospho-(1′-rac-glycerol) sodium salt;L-α-Phosphatidyl-DL-glycerol, β-oleoyl-γ-palmitoyl sodium salt;POPG-Na;POPG;1-Palmitoyl-2-oleoyl Phosphatidylglycerol Sodium Salt;POPG Sodium Salt;Sodium 2,3-Dihydroxypropyl [2-(Oleoyloxy)-3-(palmitoyloxy)propyl] Phosphate;110650;18:1(9Z));1-hexadecanoyl-2-(9Z-octadecenoyl)-sn-glycero-3-phospho-(1′racglycerol) (sodium salt);T52TI8BMQ6;1-Palmitoyl-2-oleoyl-sn-glycero-3-phosphoglycerol, sodium salt;sodium 1-palmitoyl-2-oleoyl-sn-glycero-3-(phospho-rac-(1-glycerol));POPG-Na, r-;POPG-Na, l-;POPG Na, r-;POPG Na, l-;EPG-Na;1-Palmitoyl-2-oleoyl-phosphatidyl-glycerol sodium;1-Palmitoyl-2-oleoyl-sn-glycero-3-(phospho-rac-(1-glycerol)), sodium salt;Sodium 2,3-dihydroxypropyl ((2R)-3-hexadecanoyloxy-2-((Z)-octadec-9-enoyl)oxy-propyl) phosphate;9-Octadecenoic acid (9Z)-, (1;1-Palmitoyl-2-oleyl-sn-glycero-3-phospho-rac-(1-glycerol) Sodium Salt;
标识符
InChIKey:
FJXDNGDRHUDFST-XQYKCTAGSA-M
Inchi:
1S/C40H77O10P.Na/c1-3-5-7-9-11-13-15-17-18-20-22-24-26-28-30-32-40(44)50-38(36-49-51(45,46)48-34-37(42)33-41)35-47-39(43)31-29-27-25-23-21-19-16-14-12-10-8-6-4-2;/h17-18,37-38,41-42H,3-16,19-36H2,1-2H3,(H,45,46);/q;+1/p-1/b18-17-;/t37?,38-;/m1./s1
SMILES:
P(=O)([O-])(OCC(CO)O)OC[C@@H](COC(CCCCCCCCCCCCCCC)=O)OC(CCCCCCC/C=C\CCCCCCCC)=O.[Na+]