1*2*3*4+2*3*4*5+3*4*5*6+...............+n(n+1)(n+2)(n+3)=?

网友 1

最佳答案

回答者:网友
∵1/[n·(n+1)·(n+2)收境·(n+3)]=(1/6)·[1/n-3/(n+1)+3/(n+2)-1/(n+3)]

1/(1·2·3·4)=(1/6)·(1/1-3/2+3/3-1/4)
1/(2·3·4·5)=(1/6)·(1/2-3/3+3/4-1/久民资置境活植5)
1/(3·4·5·6)=(1/6)·(1/3-3/4+3/5-1/6)
1/(4·5·6·7)=(1/6)·(1/4-3/生金官满此5+3/6-1/7)
……
1/[(n-3)·(n-2)·(n-1)·n]=(1/6)·[1/(n来自-3)-3/(n-2)+3/(n-1)-1/n]
1/[(n-2)·(n-1)技独查拉领数实空织院号·n·(n+1)]=(1/6)·360问答[1/(n-2)日争夜财岁棉农知-3/(n-1)+3/n-1/(n+1)]
1/[(n-1)·n·(n+1)·(探皮更接低导型阳n+2)]=(1/6)·[1/(n-1)-3/n+3/(n+1)-1/(n+2)]
1/[n·(n+1)·(n+2)·(n+3)]=(1/6)·[1/n-3/式罪常欢迅块那则否兰(n+1)+3/(n先研初巴室振+2)-1/(n+3)]

∴1/(1·2·3·4)+1/(2·3·4·5)+1/(3·4·5·6)+…+1/[n·(n+1)·(n+2)知等袁仅井边律印尔被·(n+3)]
=(1/6)·口分织[(1/1-3/2+3/3-1/4)+(1/2-3/3氢米供奏把属住末同+3/4-1/5)+…+1/n-3/(n+1)+3/(n+2)-1/(n+3)]
=(1/6)·[(1/1-3/2)+(1/2)+(1/3)-1/(n+1)-1/(n+2)+3/(n+2)-1/(n+3)]
=(1/6)·[1/1-2/2+1/3-1/(n+1)+2/(n+2)-1/(n+3)]
=1/18-(1/2)·(1/3)·[1/(n+1)-2/(n+2)+1/(n+3)]
=1/18-1/[2(n+1)(n+2)(n+3)]

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