645401-67-8 (双黄酮Gnidia biflavonoid 4,Gnidia biflavonoid 4)

CAS号:
645401-67-8
中文名称:
双黄酮Gnidia biflavonoid 4
英文名称:
Gnidia biflavonoid 4
分子式:
C30H22O13
分子量:
590.487889766693
植物源:

双黄酮Gnidia biflavonoid 4(645401-67-8)名称与标识符

名称

英文别名:
(2R,2'R,3S,3'R)-2,2',3,3'-Tetrahydro-3',5,5',7,7'-pentahydroxy-2-(4-hydroxyphenyl)-2'-(3,4,5-trihydroxyphenyl)-[3,8'-bi-4H-1-benzopyran]-4,4'-dione;(2S,2'R,3R,3'R)-2,2',3,3'-Tetrahydro-3',5,5',7,7'-pentahydroxy-2-(4-hydroxyphenyl)-2'-(3,4,5-trihydroxyphenyl)-[3,8'-bi-4H-1-benzopyran]-4,4'-dione;Gnidia biflavonoid 4a;

标识符

InChIKey:
JRKGPCKEYCRWST-FQYQUSJJSA-N
Inchi:
1S/C30H22O13/c31-12-3-1-10(2-4-12)28-23(25(39)20-14(33)7-13(32)8-19(20)42-28)21-15(34)9-16(35)22-26(40)27(41)29(43-30(21)22)11-5-17(36)24(38)18(37)6-11/h1-9,23,27-29,31-38,41H/t23-,27+,28+,29-/m1/s1
SMILES:
C1(C=C2O[C@@H](C3C=CC(O)=CC=3)[C@H](C3C4O[C@H](C5C=C(O)C(O)=C(O)C=5)[C@@H](O)C(C=4C(O)=CC=3O)=O)C(C2=C(O)C=1)=O)O

双黄酮Gnidia biflavonoid 4(645401-67-8)物化性质

计算特性

  • 氢键供体数量 : 9
  • 氢键受体数量 : 13
  • 重原子数量 : 43
  • 疏水参数计算参考值(XlogP) : 1.096